h^2=0.39

Solution for h^2=0.39 equation:

h^2=0.39

We move all terms to the left:

h^2-(0.39)=0

We add all the numbers together, and all the variables

h^2-0.39=0

a = 1; b = 0; c = -0.39;
Δ = b2-4ac
Δ = 02-4·1·(-0.39)
Δ = 1.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.56}}{2*1}=\frac{0-\sqrt{1.56}}{2}
=-\frac{\sqrt{}}{2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.56}}{2*1}=\frac{0+\sqrt{1.56}}{2}
=\frac{\sqrt{}}{2}
$